Lee Westwood rallies and leads in Orlando by one hit

The Briton recovered ten positions to finish the third round with 65 strokes. The best of the day was Keegan Bradley (-8).

The Englishman Lee Westwood took the lead this Saturday in the Arnold Palmer Invitational tournament, which is played at the Bay Hill Club & Lodge, in Orlando (Florida), at the end of the third round with 65 strokes (-7) and accumulating 205 (-11 ) one day from the end. Westwood, 47, climbed 10 places in the rankings today.

With one more blow finished the Canadian Corey Conners, who led the first two rounds and now shares the second place with the American Bryson DeChambeau. Conners and DeChambeau have 206 hits (-10). Two other Americans, Jordan Spieth and Keegan Bradley, are in fourth place with 207 hits (-9). Bradley had the best record of the day with 64 impacts (-8) .

Leader Westwood delivered a card with an 'eagle', on par 5 of the 16th hole, eight birdies, including the one he completed on the last hole, although he also committed three 'bogeys'. In his crossing the Canadian Conners produced three 'birdies' but committed two 'bogeys'. Better was the American DeChambeau, who offered six birdies and two bogeys. His compatriot Keegan Bradley, 34, had the best performance of the day with six birdies and an eagle achieved on par 5 of hole 6.

The Argentine Emiliano Grillo left a record of 68 strokes (-4) with six birdies and two bogeys. He accumulates 213 strokes (-3) and today he advanced 24 points to share the twenty-ninth step with five rivals. Colombian Sebastián Muñoz finished with 72 (par) and added 216 strokes (par). Today he lost 12 places in the classification and fell to 50.

Photos from as.com
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